**i) 8, 10, 12, 14, ?**

a) 18

b) 15

c) 26

d) 16

Correct Option: (d)

Arithmetic progression type of question. +2 difference

**ii) 19, 25, 32, 40, ?, 59**

a) 46

b) 49

c) 55

d) 51

Correct Option: (b)

Observe difference between two terms. It is not randomly incrementing. So it might be arithmetic progression type of question. Let’s try to solve it. Difference is in increasing order. Difference is +6, +7, +8, +9 .. So, 40+9=49

a) 432

b) 864

c) 1080

d) 1512

Correct Option: (c)

As we can see that difference between two terms is high. So it there is possibilities that this is geometric progression type of question. Let’s try to solve it. *2, *3, *4, *5 … So 216*5=1080

**iv) 216, 72, 36, 12, ?, 2**

a) 8

b) 6

c) 4

d) 3

Correct Option: (b)

As we can see from series that difference is random. So might be geometric progression type of series and more on terms are in decreasing order, so it must be division operation applied. Difference is /3, /2, /3, /2 … So, 12/2=6

**v) 8, 27, 64, 125, ?, 343**

a) 312

b) 216

c) 189

d) 225

Correct Option: (b)

We can clearly see that 8, 27, 64 are the cubes of 2, 3, 4 respectively. So after 125 there must be 6^{3} = 216. So answer is 216

**vi) 1, 4, 27, 16, 125, ?, 343**

a) 216

b) 25

c) 36

d) 225

Correct Option: (c)

Problem has fluctuated terms and they are in random order. As we can see, all the terms are combination of squares and cubes. Let’s find out pattern between terms 4=2^{2}, 27=3^{3}, 16=4^{2}, 125=5^{3} and 343=7^{3}. So missing term will be 62=3^{6}. Pattern is like 2^{2}, 3^{3}, 4^{2}, 5^{3}, 6^{2}…

**vii) 2, 5, 10, 17, 28, ?**

a) 37

b) 35

c) 41

d) 40

Correct Option: (c)

Let’s find out difference between two terms. We are getting difference like +3, +5, +7, +11 all differences are prime numbers, next prime number after 11 is 13. So answer is 28+13=41

**viii) 21, 34, 55, 89, 144, ?, 377**

a) 199

b) 233

c) 220

d) 241

Correct Option: (b)

First we have to find out difference between two terms because numbers are not randomly increasing. We got differences are +13, +21, +34, +55. Differences clearly show the Fibonacci series (i.e. Addition of previous 2 numbers). So answer is 144+89=233

**ix) 41, 93, 165, 257, 369, ?**

a) 4861

b) 4211

c) 4911

d) 4411

Correct Option: (c)

Let’s find out differences, But from differences we are not getting any kind of relations. This is miscellaneous type of question in which, we can break down numbers. Let’s break down each and every numbers. So we got proper logic for this series i.e. first half is the squares of some continuous numbers like 2, 3, 4, 5, 6 and second half is continuous odd numbers

B) Alphabetical Series

**Examples:**

**i) CEH, ?, OQT, UWZ**

a) ACG

b) IKN

c) FGJ

d) KLM

Correct Option: (b)

2^{nd} letter is obtained by skipping 1 letter in alphabet from 1^{st} letter and 3^{rd} letter is obtained by skipping 2 letters from 2^{nd} letter

**ii) BDA, FHE, ?, NPM**

a) JKI

b) IMJ

c) JLI

d) INJ

Correct Option: (c)

Series starts from 3rd letter. i.e. I

1^{st} letter (J)- next letter in the alphabet of the 3rd letter.

2^{nd} letter (L)- skip 1 letter in the alphabet from 1st letter(J)

**iii) HFD, NLJ, ??O, XVT**

a) PQ

b) SQ

c) QP

d) QS

Correct Option: (b)

Series is in reverse order. i.e. series starts from the last letter of the word. Then keep on skipping 1 lette

**iv) AEFG, BHIJ, ?, DNOP**

a) CIJK

b) CFGH

c) CKLM

d) CKMN

Correct Option: (c)

There are two series in this question. 1^{st} series is with the first letter only- ABCD. The second series involve the remaining letters- EFG, HIJ, KLM and NOP

C) Alphanumeric

In this type of series, problems asked with combination of alphabet, symbols and numbers.

**i) 2E2, 1H9, 1K6, 1N3, ?**

a) 1P4

b) 1J9

c) 1Q0

d) 1R8

Correct Option: (c)

This is alphanumeric type of question. In first term 2E2, E is 22^{nd} letter from Z – So, 2E2.

Similarly, K is 16^{th} letter from Z – So, 1K6.

So, Answer is 1Q0 – M is 10^{th} letter from Z

**ii) H8, L12, O15, S19, ?**

a) U21

b) W23

c) V22

d) Y25

Correct Option: (c)

Alphabet letter of first term is H and number in it is 8 i.e. numerical position of H in alphabet. Same way in second term 12 is the numerical position of L in alphabet. Let’s find out difference between two terms. So, we got differences are +3, +2, +3, +2… So next term will be S + 2 letters from S = V. Thus answer is V22