i) 8, 10, 12, 14, ?
a) 18
b) 15
c) 26
d) 16
Correct Option: (d)
Arithmetic progression type of question. +2 difference
ii) 19, 25, 32, 40, ?, 59
a) 46
b) 49
c) 55
d) 51
Correct Option: (b)
Observe difference between two terms. It is not randomly incrementing. So it might be arithmetic progression type of question. Let’s try to solve it. Difference is in increasing order. Difference is +6, +7, +8, +9 .. So, 40+9=49
a) 432
b) 864
c) 1080
d) 1512
Correct Option: (c)
As we can see that difference between two terms is high. So it there is possibilities that this is geometric progression type of question. Let’s try to solve it. *2, *3, *4, *5 … So 216*5=1080
iv) 216, 72, 36, 12, ?, 2
a) 8
b) 6
c) 4
d) 3
Correct Option: (b)
As we can see from series that difference is random. So might be geometric progression type of series and more on terms are in decreasing order, so it must be division operation applied. Difference is /3, /2, /3, /2 … So, 12/2=6
v) 8, 27, 64, 125, ?, 343
a) 312
b) 216
c) 189
d) 225
Correct Option: (b)
We can clearly see that 8, 27, 64 are the cubes of 2, 3, 4 respectively. So after 125 there must be 63 = 216. So answer is 216
vi) 1, 4, 27, 16, 125, ?, 343
a) 216
b) 25
c) 36
d) 225
Correct Option: (c)
Problem has fluctuated terms and they are in random order. As we can see, all the terms are combination of squares and cubes. Let’s find out pattern between terms 4=22, 27=33, 16=42, 125=53 and 343=73. So missing term will be 62=36. Pattern is like 22, 33, 42, 53, 62…
vii) 2, 5, 10, 17, 28, ?
a) 37
b) 35
c) 41
d) 40
Correct Option: (c)
Let’s find out difference between two terms. We are getting difference like +3, +5, +7, +11 all differences are prime numbers, next prime number after 11 is 13. So answer is 28+13=41
viii) 21, 34, 55, 89, 144, ?, 377
a) 199
b) 233
c) 220
d) 241
Correct Option: (b)
First we have to find out difference between two terms because numbers are not randomly increasing. We got differences are +13, +21, +34, +55. Differences clearly show the Fibonacci series (i.e. Addition of previous 2 numbers). So answer is 144+89=233
ix) 41, 93, 165, 257, 369, ?
a) 4861
b) 4211
c) 4911
d) 4411
Correct Option: (c)
Let’s find out differences, But from differences we are not getting any kind of relations. This is miscellaneous type of question in which, we can break down numbers. Let’s break down each and every numbers. So we got proper logic for this series i.e. first half is the squares of some continuous numbers like 2, 3, 4, 5, 6 and second half is continuous odd numbers
B) Alphabetical Series
Examples:
i) CEH, ?, OQT, UWZ
a) ACG
b) IKN
c) FGJ
d) KLM
Correct Option: (b)
2nd letter is obtained by skipping 1 letter in alphabet from 1st letter and 3rd letter is obtained by skipping 2 letters from 2nd letter
ii) BDA, FHE, ?, NPM
a) JKI
b) IMJ
c) JLI
d) INJ
Correct Option: (c)
Series starts from 3rd letter. i.e. I
1st letter (J)- next letter in the alphabet of the 3rd letter.
2nd letter (L)- skip 1 letter in the alphabet from 1st letter(J)
iii) HFD, NLJ, ??O, XVT
a) PQ
b) SQ
c) QP
d) QS
Correct Option: (b)
Series is in reverse order. i.e. series starts from the last letter of the word. Then keep on skipping 1 lette
iv) AEFG, BHIJ, ?, DNOP
a) CIJK
b) CFGH
c) CKLM
d) CKMN
Correct Option: (c)
There are two series in this question. 1st series is with the first letter only- ABCD. The second series involve the remaining letters- EFG, HIJ, KLM and NOP
C) Alphanumeric
In this type of series, problems asked with combination of alphabet, symbols and numbers.
i) 2E2, 1H9, 1K6, 1N3, ?
a) 1P4
b) 1J9
c) 1Q0
d) 1R8
Correct Option: (c)
This is alphanumeric type of question. In first term 2E2, E is 22nd letter from Z – So, 2E2.
Similarly, K is 16th letter from Z – So, 1K6.
So, Answer is 1Q0 – M is 10th letter from Z
ii) H8, L12, O15, S19, ?
a) U21
b) W23
c) V22
d) Y25
Correct Option: (c)
Alphabet letter of first term is H and number in it is 8 i.e. numerical position of H in alphabet. Same way in second term 12 is the numerical position of L in alphabet. Let’s find out difference between two terms. So, we got differences are +3, +2, +3, +2… So next term will be S + 2 letters from S = V. Thus answer is V22